5v^2-12v-32=0

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Solution for 5v^2-12v-32=0 equation: 



5v^2-12v-32=0

a = 5; b = -12; c = -32;
Δ = b2-4ac
Δ = -122-4·5·(-32)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-28}{2*5}=\frac{-16}{10}
=-1+3/5
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+28}{2*5}=\frac{40}{10}
=4
$

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